For the reaction 2 SO₂(g)+ O₂(g)$\rarr$ 2 SO₃(g), if initially P(SO₂)= 1.2 atm, P(O₂)= 1.8 atm, and P(SO₃)= 2.1 atm, calculate $\Delta$G for this reaction at 25°C.The following data is valid at 25°C: A)-140.0 kJ/mol B)-137.6 kJ/mol C)-138.7 kJ/mol D)1,174.7 kJ/mol E)-141.3 kJ/mol

Question

Quizplus · Accepted Answer

We can use the formula ΔG = ΔH - TΔS to solve this problem. We need to find ΔG for the reaction at 25°C, which is 298 K.

To use this formula, we need to find ΔH and ΔS for the reaction. We can do this by looking up the standard enthalpy (ΔH°) and entropy (ΔS°) values for the reaction components and using them to calculate the values for the reaction. We can then use these values to calculate ΔG.

Using the given data, we can write the balanced equation for the reaction:
2 SO2(g) + O2(g) → 2 SO3(g)

The standard enthalpy of formation for SO2 is -296.8 kJ/mol, for O2 is 0 kJ/mol, and for SO3 is -395.7 kJ/mol. Using these values, we can calculate ΔH° for the reaction:
ΔH° = (2 mol x -296.8 kJ/mol) + (1 mol x 0 kJ/mol) - (2 mol x -395.7 kJ/mol) = -198.6 kJ/mol

The standard entropy of formation for SO2 is 248.2 J/mol·K, for O2 is 205.0 J/mol·K, and for SO3 is 256.2 J/mol·K. Using these values, we can calculate ΔS° for the reaction:
ΔS° = (2 mol x 248.2 J/mol·K) + (1 mol x 205.0 J/mol·K) - (2 mol x 256.2 J/mol·K) = -70.8 J/mol·K

Now we can use the formula ΔG = ΔH - TΔS to calculate ΔG for the reaction at 25°C:
ΔG = -198.6 kJ/mol - (298 K x (-0.0708 kJ/mol·K)) = -138.7 kJ/mol

Therefore, the best choice is C (-138.7 kJ/mol).

For the Reaction 2 SO2(g)+ O2(g) →\rarr→ 2 SO3(g), If Initially P(SO2)= 1

For the Reaction 2 SO₂(g)+ O₂(g) $\rarr$ 2 SO₃(g), If Initially P(SO₂)= 1