Calculate the pH of a 3.5 × 10^-3 M HNO₃ solution. A)-2.46 B)0.54 C)2.46 D)3.00 E)3.46

Question

Quizplus · Accepted Answer

HNO₃ can be written as H2SO4, which is sulfuric acid. The formula for sulfuric acid dissociation is H2SO4 + H2O ↔ H3O+ + HSO4-. The acid dissociation constant (Ka) for sulfuric acid is 1.2 × 10^-2. To calculate the pH of the solution, we need to calculate the concentration of H3O+ ions: [H3O+] = Ka * [HSO4-] / [H2SO4] [H2SO4] = 3.5 × 10^-1 M (from the given concentration) [HSO4-] = [H2SO4] because H2SO4 dissociates only once [H3O+] = (1.2 × 10^-2) * (3.5 × 10^-1) / (3.5 × 10^-1) = 1.2 × 10^-2 pH = -log[H3O+] = -log(1.2 × 10^-2) = 2.46 Therefore, the correct answer is C) 2.46.

Calculate the PH of a 3