Given H₂(g)+ (1/2)O₂(g)$\rarr$H₂O(l), $\Delta$H° = -286 kJ/mol, determine the standard enthalpy change for the reaction 2H₂O(l)$\rarr$2H₂(g)+ O₂(g). A)($\Delta$H° = -286 kJ/mol) B)($\Delta$H° = +286 kJ/mol) C)($\Delta$H° = -572 kJ/mol) D)($\Delta$H° = +572 kJ/mol) E)($\Delta$H° = -143 kJ/mol)

Question

Quizplus · Accepted Answer

The given reaction is the reverse of the formation of water, so the sign of the enthalpy change is reversed. Additionally, the reaction is doubled, so the enthalpy change is also doubled: +286 kJ/mol * 2 = +572 kJ/mol.

Given H2(g)+ (1/2)O2(g) →\rarr→ H2O(l) Δ\DeltaΔ H° = -286 KJ/mol, Determine the Standard Enthalpy Change for Determine

Given H₂(g)+ (1/2)O₂(g) $\rarr$ H₂O(l) $\Delta$ H° = -286 KJ/mol, Determine the Standard Enthalpy Change for Determine