A 5.00 mL sample of a nitric acid solution is titrated with 33.5 mL of 0.201 M NaOH.What is the molarity of the nitric acid solution?
A)0.0300 M
B)0.149 M
C)1.35 M
D)6.7 M
E)0.522 M

Question

Quizplus · Accepted Answer

To find the molarity of the nitric acid solution, use the formula M1V1 = M2V2. Here, M1 is the molarity of HNO3, V1 is the volume of HNO3, M2 is the molarity of NaOH, and V2 is the volume of NaOH. Plugging in the values: M1 * 5.00 mL = 0.201 M * 33.5 mL. Solving for M1 gives M1 = (0.201 M * 33.5 mL) / 5.00 mL = 1.35 M.

A 500 ML Sample of a Nitric Acid Solution Is Titrated