An object is 12.0 cm from the surface of a spherical Christmas tree ornament that is 10.0 cm in diameter.What is the magnification of the image?
A) −0.500
B) −0.200
C) +0.172
D) +0.143

Question

Quizplus · Accepted Answer

The image is virtual and upright, so the magnification is positive. The object distance is 12.0 cm and the image distance is 20.0 cm, so the magnification is:$$m = - \frac{20.0 cm}{12.0 cm} = +0.172$$

An Object Is 12