Carbon has a negative temperature coefficient of resistance of -0.5 × 10^-3 (°C)−¹.What temperature increase would result in a resistance decrease of 3% for a carbon resistor? A) 60°C B) 100°C C) 20°C D) 40°C

Question

Quizplus · Accepted Answer

The resistance change is given by ΔR/R = αΔT, where α is the temperature coefficient. For a 3% decrease, ΔR/R = -0.03. Solving -0.03 = -0.5 × 10^-3 × ΔT gives ΔT = 60°C.

Carbon Has a Negative Temperature Coefficient of Resistance of -0