A 1 000-V battery,a 3 000-Ω resistor,and a 0.50-µF capacitor are connected in series with a switch.The capacitor is initially uncharged.What is the value of the current the moment after the switch is closed?
A) 0.39 A
B) 0.33 A
C) 0.84 A
D) 2 000 A

Question

A 1 000-V battery,a 3 000-Ω resistor,and a 0.50-µF capacitor are connected in series with a switch.The capacitor is initially uncharged.What is the value of the current the moment after the switch is closed? 
A) 0.39 A 
B) 0.33 A 
C) 0.84 A 
D) 2 000 A

Quizplus · Accepted Answer

The current in the circuit at the moment after the switch is closed can be found by using the formula:

I = V/R

where I is the current, V is the voltage, and R is the total resistance.

First, we need to find the total resistance of the circuit:

Rtotal = R1 + R2

where R1 is the resistance of the 3 000-Ω resistor and R2 is the impedance of the 0.50-µF capacitor.

The impedance of the capacitor can be found using the formula:

Z = 1/(2πfC)

where Z is the impedance, f is the frequency (which is assumed to be zero in this case), and C is the capacitance.

So, Z = 1/(2π(0)(0.50x10^-6)) = infinity

This means that the capacitor acts as an open circuit and can be ignored in calculating the total resistance of the circuit.

Therefore, Rtotal = R1 = 3 000 Ω.

Now, we can find the current:

I = V/Rtotal = 1 000 V/3 000 Ω = 0.33 A

So, the answer is B: 0.33 A.

A 1 000-V Battery,a 3 000-Ω Resistor,and a 0