A mass of 0.4 kg,attached to a spring with a spring constant of 80 N/m,is set into simple harmonic motion.What is the magnitude of the acceleration of the mass when at its maximum displacement of 0.2 m from the equilibrium position?

Question

Quizplus · Accepted Answer

The acceleration at maximum displacement is given by a = (k/m) * x, where k is the spring constant, m is the mass, and x is the displacement. Substituting the given values: a = (80 N/m / 0.4 kg) * 0.2 m = 40 m/s².

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