In a standard normal distribution,the probability P(-1.00

Question

In a standard normal distribution,the probability P(-1.00< Z < 1.20)is the same as
A)P(1<Z<1.20)- P(0<Z<1.00).
B)P(1<Z<1.20)- 2*P(0<Z<1.00).
C)2*P(1<Z<1.20)- P(0<Z<1.00).
D)P(1<Z<1.20)+ 2*P(0<Z<1.00).

Quizplus · Accepted Answer

The probability P(-1.00 < Z < 1.20) can be split into two parts: P(0 < Z < 1.00) and P(0 < Z < 1.20). The symmetry of the normal distribution implies P(-1.00 < Z < 0) = P(0 < Z < 1.00). Therefore, P(-1.00 < Z < 1.20) = P(0 < Z < 1.20) + P(0 < Z < 1.00), which matches option D.

In a Standard Normal Distribution,the Probability P(-1