For which of the following aqueous solutions would one expect to have the largest van't Hoff factor (i)? A)0.500 m K₂SO₄ B)0.500 m NaCl C)0.500 m C₆H₁₂O₆ (glucose) D)0.050 m K₂SO₄ E)0.050 m NaCl

Question

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The van't Hoff factor (i) is a measure of the effect of solute particles on the colligative properties of a solution. For ionic compounds, it corresponds to the number of ions produced when the compound dissolves. K₂SO₄ (potassium permanganate, KMnO4) dissociates into 2 ions (K+ and MnO4-), similar to NaCl (which dissociates into Na+ and Cl-). However, the concentration of KMnO4 in choice A is higher than in choice D, making its effective van't Hoff factor larger due to the higher concentration of ions in solution. Glucose (C6H12O6) does not dissociate into ions; thus, its van't Hoff factor is 1, making it the lowest among the options. Therefore, the correct answer is A, due to the higher concentration of KMnO4, which leads to a larger number of ions in solution compared to the other options.

For Which of the Following Aqueous Solutions Would One Expect