Nickel has a face-centered cubic structure and has a density of 8.90 g/cm³.What is its atomic radius? A)125 pm B)249 pm C)353 pm D)997 pm

Question

Quizplus · Accepted Answer

The density of a face-centered cubic structure is given by:$$ho = \frac{4AM}{a^3N_A}$$where $ho$ is the density, $A$ is the atomic weight, $M$ is the molar mass, $a$ is the edge length of the unit cell, $N_A$ is Avogadro's number.We can rearrange this equation to solve for the atomic radius:$$r = \frac{a\sqrt{2}}{4}$$Substituting the given values into this equation, we get:$$r = \frac{(3.52 	imes 10^{-8} 	ext{ cm})\sqrt{2}}{4} = 2.49 	imes 10^{-8} 	ext{ cm} = 249 	ext{ pm}$$Therefore, the atomic radius of nickel is 249 pm.

Nickel Has a Face-Centered Cubic Structure and Has a Density