For the scores in the following frequency distribution table,the mean is about M = 3.? $$\begin{array} { l l }
\mathrm { X } & \mathrm { f } \
\hline 4 & 1 \
3 & 4 \
2 & 2
\end{array}$$

Question

For the scores in the following frequency distribution table,the mean is about M = 3.? $$\begin{array} { l l } 
\mathrm { X } & \mathrm { f } \
\hline 4 & 1 \
3 & 4 \
2 & 2
\end{array}$$

Quizplus · Accepted Answer

To find the mean, multiply each score (X) by its frequency (f), sum these products, and divide by the total frequency. (4*1 + 3*4 + 2*2) / (1+4+2) = 20/7 ≈ 2.86, which is about 3.

For the Scores in the Following Frequency Distribution Table,the Mean Xf413422\begin{array} { l l } \mathrm { X } & \mathrm { f } \\\hline 4 & 1 \\3 & 4 \\2 & 2\end{array}X432​f142​​

For the Scores in the Following Frequency Distribution Table,the Mean $\begin{array} { l l } \mathrm { X } & \mathrm { f } \\\hline 4 & 1 \\3 & 4 \\2 & 2\end{array}$