Calculate the Standard Enthalpy Change for the Reaction 2C₈H₁₈(l) $\rarr$ 16CO(g) + 18H₂O(l)

Calculate the standard enthalpy change for the reaction 2C₈H₁₈(l) + 17O₂(g) $\rarr$ 16CO(g) + 18H₂O(l) .Given
$\begin{array}{ll}2 \mathrm{C}_{8} \mathrm{H}_{18}(\mathrm{l}) +25 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 16 \mathrm{CO}_{2}(\mathrm{g}) +18 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) & \Delta \mathrm{H}^{\circ}=-11,020 \mathrm{~kJ} / \mathrm{mol} \\2 \mathrm{CO}(\mathrm{g}) +\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{CO}_{2}(\mathrm{g}) & \Delta \mathrm{H}^{\circ}=-566.0 \mathrm{~kJ} / \mathrm{mol}\end{array}$

A) -10.450 kJ/mol
B) -6,492 kJ/mol
C) 6,492 kJ/mol
D) 10,450 kJ/mol
E) 15,550 kJ/mol