The equilibrium expression for the hydrolysis of a weak base, A^-, in water is: A) K_b = [A^-]/[OH^-][H₃O⁺] B) K_b = [OH^-][H₃O⁺]/[A^-] C) K_b = [OH^-][HA]/[A^-] D) K_b = [OH^-][A^-]/[HA] E) K_b = [OH^-][HA]/[A^-][H₃O⁺]

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The Answer of The equilibrium expression for the hydrolysis of a weak base, A^-, in water is: A) K_b = [A^-]/[OH^-][H₃O⁺] B) K_b = [OH^-][H₃O⁺]/[A^-] C) K_b = [OH^-][HA]/[A^-] D) K_b = [OH^-][A^-]/[HA] E) K_b = [OH^-][HA]/[A^-][H₃O⁺]

The Equilibrium Expression for the Hydrolysis of a Weak Base