For any pure substance, if $\Delta$H_f^$\circ$ = 0 and $\Delta$G_f^$\circ$ = 0, then S^$\circ$ = 0.

Question

Quizplus · Accepted Answer

The given statement appears to be a mix of symbols and notations that don't directly relate to standard thermodynamic equations. However, interpreting the intent: if ΔH° = 0 and ΔG° = 0, it does not necessarily imply that ΔS° = 0. ΔG° = ΔH° - TΔS°, so ΔS° can be non-zero if ΔH° and ΔG° are both zero, depending on the temperature (T).

For Any Pure Substance, If Δ\DeltaΔ Hf ∘\circ∘ = 0 And Δ\DeltaΔ

For Any Pure Substance, If $\Delta$ H_f^$\circ$ = 0 And $\Delta$