What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall redox equation: 5Fe²⁺(aq) + MnO₄^-(aq) + 8H⁺(aq) $\rarr$5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(l)

Question

Quizplus · Accepted Answer

To determine the number of moles of electrons exchanged, we need to balance the redox equation by assigning oxidation states and determining the half-reactions. The half-reactions are:
5Fe2+ → 5Fe3+ + 5e- (oxidation)
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O (reduction)
Multiplying the oxidation half-reaction by 5 and adding it to the reduction half-reaction, we get:
5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O
So, 5 moles of electrons are exchanged between the oxidizing agent (MnO4-) and the reducing agent (Fe2+). Therefore, the answer is C.

What Is the Total Number of Moles (N) of Electrons →\rarr→

What Is the Total Number of Moles (N) of Electrons $\rarr$