A car traveling at 4.0 m/s has a constant acceleration of 2.0 m/s².After 3.0 seconds,the distance traveled during the acceleration is A) 21 m. B) 17 m. C) 10 m. D) 13 m. E) 9 m.

Question

Quizplus · Accepted Answer

The distance traveled under constant acceleration can be calculated using the formula: $ s = ut + \frac{1}{2}at^2 $, where $ u = 4.0 \, \text{m/s} $, $ a = 2.0 \, \text{m/s}^2 $, and $ t = 3.0 \, \text{s} $. Plugging in these values, $ s = 4.0 \times 3.0 + \frac{1}{2} \times 2.0 \times (3.0)^2 = 12 + 9 = 21 \, \text{m} $.

A Car Traveling at 4