A projectile is projected from the origin with a velocity of 45.0 m/s at an angle of 30.0 degrees above the horizontal.What is the location of the projectile 3.00 seconds later?
A) X = 85.0 m,Y = 37.0 m
B) X = 117.0 m,Y = 23.4 m
C) X = 37.0 m,Y = 117.0 m
D) X = 23.4 m,Y = 37.0 m
E) X = 85.0 m,Y = 23.4 m

Question

Quizplus · Accepted Answer

Using the kinematic equations, we can determine the horizontal and vertical components of the projectile's displacement after 3 seconds:
Horizontal displacement: x = v0*cos(theta)*t = 45.0*cos(30.0)*3.00 = 117.0 m
Vertical displacement: y = v0*sin(theta)*t - (1/2)*g*t^2 = 45.0*sin(30.0)*3.00 - (1/2)*9.81*(3.00)^2 = 23.4 m
Therefore, the location of the projectile after 3 seconds is (117.0 m, 23.4 m), which corresponds to choice B.

A Projectile Is Projected from the Origin with a Velocity