A projectile is projected from the origin with a velocity of 15.0 m/s at an angle of 30.0 degrees above the horizontal.What is the location of the projectile 2.00 seconds later?
A) X = 4.60 m,Y = 9.60 m
B) X = -26.0 m,Y = -26.0 m
C) X = -36.0 m,Y = -4.60 m
D) X = 26.0 m,Y = -4.60 m
E) X = 46.0 m,Y = 4.60 m

Question

Quizplus · Accepted Answer

The horizontal and vertical components of the velocity are 15*cos(30) and 15*sin(30) respectively. After 2 seconds, the horizontal position is 15*cos(30)*2 = 26.0 m, and the vertical position is 15*sin(30)*2 - 0.5*9.8*2^2 = -4.60 m.

A Projectile Is Projected from the Origin with a Velocity