In order to conserve fuel,you modify your car by removing 100 kg of excess weight.How much energy is saved each time you accelerate from 0 to 100 km/hr (62 mph)? A) 2.86 $\times$ 10² J B) 2.86 $\times$ 10⁴ J C) 3.86 $\times$ 10⁴ J D) 3.86 $\times$ 10² J

Question

Quizplus · Accepted Answer

The energy saved when accelerating a car is given by:
E = (1/2)mv^2
where m is the mass of the car and v is the velocity.
When the car loses 100 kg of excess weight, its mass decreases by m' = 100 kg.
Assuming the velocity remains the same, the energy saved when accelerating the modified car from 0 to 100 km/hr is:
E' = (1/2)(m - m')v^2 - (1/2)mv^2
Substituting the values, we get:
E' = (1/2)(850-100)(27.78)^2 - (1/2)(850)(27.78)^2
E' = 3.86 x 10^12 J
Therefore, the answer is (C) 3.86 x 10^12 J.

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