If 1.00 mol of oxygen is heated at constant pressure of 1.00 atm from 10.0$^{\circ}$C to 25.0$^{\circ}$C.What is the change of volume of the gas in this process?
A) 1.23 L
B) 0.86 L
C) 1.88 L
D) 2.09 L

Question

Quizplus · Accepted Answer

The change in volume can be calculated using the ideal gas law and the relation $ \Delta V = nR\Delta T/P $. Here, $ n = 1.00 $ mol, $ R = 0.0821 $ L·atm/mol·K, $ \Delta T = 15 $ K, and $ P = 1.00 $ atm. Substituting these values gives $ \Delta V = 1.23 $ L.

If 100 Mol of Oxygen Is Heated at Constant Pressure of of 1.00