What is the magnitude of the acceleration of an electron when in an electric field of 7.0 $\times$ 10⁴ N/C? A) 3.0 $\times$ 10⁸ m/s² B) 1.2 $\times$ 10¹⁶ m/s² C) 7.7 $\times$ 10³⁴ m/s² D) 8.6 $\times$ 10^{20.00 m}/s² E) 7.0 $\times$ 10⁴ m/s²

Question

Quizplus · Accepted Answer

The acceleration of an electron in an electric field is given by a = F/m = eE/m, where e is the charge of the electron (1.6 * 10^-19 C), E is the electric field (7.0 * 10^4 N/C), and m is the mass of the electron (9.11 * 10^-31 kg). Calculating gives a = (1.6 * 10^-19 C * 7.0 * 10^4 N/C) / (9.11 * 10^-31 kg) = 1.2 * 10^16 m/s^2.

What Is the Magnitude of the Acceleration of an Electron ×\times×

What Is the Magnitude of the Acceleration of an Electron $\times$