Complete the following nuclear equation: $\begin{array} { c }
210\
84
\end{array}$ Po ? ?? + $\begin{array} { c }
4\
2
\end{array}$ He
A) $\begin{array} { c }
210\
84
\end{array}$ Po
B) $\begin{array} { c }
206\
82
\end{array}$ Pb
C) $\begin{array} { c }
210\
82
\end{array}$ Pb
D) $\begin{array} { c }
214\
86
\end{array}$ Rn
E)none of the above

Question

Complete the following nuclear equation: $\begin{array} { c } 
210\
84
\end{array}$ Po ? ?? + $\begin{array} { c } 
4\
2
\end{array}$ He
A) $\begin{array} { c } 
210\
84
\end{array}$ Po
B) $\begin{array} { c } 
206\
82
\end{array}$ Pb
C) $\begin{array} { c } 
210\
82
\end{array}$ Pb
D) $\begin{array} { c } 
214\
86
\end{array}$ Rn
E)none of the above

Quizplus · Accepted Answer

This equation represents alpha decay, where a polonium (Po) nucleus emits an alpha particle ($\begin{array} { c } 4\2 \end{array}$ He). The mass number decreases by 4 (from 210 to 206) and the atomic number decreases by 2 (from 84 to 82), resulting in lead (Pb), making option B correct.

Complete the Following Nuclear Equation 21084\begin{array} { c } 210\\84\end{array}21084​ Po ? ??

Complete the Following Nuclear Equation $\begin{array} { c } 210\\84\end{array}$ Po ? ??