What volume of a 2.00 M KCl solution is required to prepare 500.mL of a 0.100 M KCl solution?
A)0.0400 mL
B)25.0 mL
C)2.00 mL
D)1.00 × mL
E)5.00 × mL

Question

What volume of a 2.00 M KCl solution is required to prepare 500.mL of a 0.100 M KCl solution?
A)0.0400 mL 
B)25.0 mL 
C)2.00 mL 
D)1.00 × mL 
E)5.00 × mL

Quizplus · Accepted Answer

Use the formula: M1V1 = M2V2
where,
M1 = 2.00 M (initial concentration)
V1 = volume of the solution to be prepared (unknown)
M2 = 0.100 M (final concentration)
V2 = 500. mL

Rearranging the formula, we get:
V1 = (M2V2) / M1
V1 = (0.100 M)(500. mL) / 2.00 M
V1 = 25.0 mL

Therefore, 25.0 mL of the 2.00 M KCl solution is required to prepare 500 mL of a 0.100 M KCl solution. Option B) is the best choice.

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