A 50.0-mH inductor is connected in series with a 2500-Ω resistor. What is the phase angle at 3000 Hz?
A) 20.7°
B) - 20.7°
C) -75.9°
D) 75.9°
E) 90.0°

Question

Quizplus · Accepted Answer

The phase angle is given by:$$\phi = \arctan\left(\frac{XL}{R}\right)$$where:* XL is the inductive reactance* R is the resistanceAt 3000 Hz, the inductive reactance is:$$XL = 2\pi f L = 2\pi (3000 Hz) (50.0 mH) = 942.5 \Omega$$Therefore, the phase angle is:$$\phi = \arctan\left(\frac{942.5 \Omega}{2500 \Omega}\right) = 20.7°$$

A 500-MH Inductor Is Connected in Series with a 2500-Ω Resistor