When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displaced from its equilibrium position and undergoes simple harmonic oscillations. What is the period of the oscillations?
A) 0.695 s
B) 0.483 s
C) 0.286 s
D) 0.0769 s
E) 1.44 s

Question

Quizplus · Accepted Answer

The spring constant k can be found using Hooke's Law: F = kx, where F = mg. Then, the period T of oscillation is given by T = 2π√(m/k).

When a Mass of 0