A car starts from rest and accelerates at 6.00 m/s². How far does it travel in 3.00 s? A) 9.00 m B) 18.0 m C) 27.0 m D) 36.0 m E) 54.0 m

Question

Quizplus · Accepted Answer

We can use the equation:

d = ut + 1/2 at^2

Where:

u = initial velocity = 0 m/s 
a = acceleration = 6.00 m/s^2 
t = time = 3.00 s

Plugging in the values, we get:

d = 0 + 1/2 (6.00) (3.00)^2 
d = 27.0 m

Therefore, the car travels a distance of 27.0 m in 3.00 s.

The answer is (C).

A Car Starts from Rest and Accelerates at 6