A solution contains 2.2 × 10^-3M in Cu²⁺ and 0.33 M in LiCN.If the K_f for Cu(CN)₄^2- is 1.0 × 10²⁵,how much copper ion remains at equilibrium? A)3.8 × 10^-24 M B)1.9 × 10^-26 M C)6.7 × 10^-28 M D)2.9 × 10^-27 M E)4.6 × 10^-25M

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Quizplus · Accepted Answer

The formation constant (Kf) is very large, indicating that almost all Cu²⁺ ions will form the complex Cu(CN)₄²⁻. Using the Kf expression and assuming nearly complete conversion, the remaining concentration of Cu²⁺ is extremely small, calculated to be approximately 1.9 × 10⁻²⁶ M.

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