How many moles of nitrogen will react with 380 mL of hydrogen at -30°C and 200 mm Hg? N₂(g)+ 3 H₂(g)→ 2 NH₃(g) A) 0.0150 mol B) 0.00782 mol C) 0.00501 mol D) 0.00167 mol E) 0.0382 mol

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First, convert the volume of hydrogen to moles using the ideal gas law: PV = nRT. Convert 380 mL to liters (0.380 L), -30°C to Kelvin (243 K), and 200 mm Hg to atm (0.263 atm). Using R = 0.0821 L·atm/mol·K, n = (0.263 atm * 0.380 L) / (0.0821 L·atm/mol·K * 243 K) = 0.00501 mol H₂. According to the stoichiometry of the reaction, 1 mole of N₂ reacts with 3 moles of H₂, so 0.00501 mol H₂ corresponds to 0.00501/3 = 0.00167 mol N₂.

How Many Moles of Nitrogen Will React with 380 ML