Table 15-1
Labor Data for Aridia
$$\begin{array} { | l | c | c | c | }
\hline \text { Year } & \mathbf { 2 0 1 0 } & \mathbf { 2 0 1 1 } & \mathbf { 2 0 1 2 } \
\hline \text { Adult population } & 2000 & 3000 & 3200 \
\hline \text { Number of emplayed } & 1400 & 1300 & 1600 \
\hline \text { Number of unemplayed } & 200 & 600 & 200 \
\hline
\end{array}$$
-Refer to Table 15-1. The unemployment rate of Aridia
A)increased from 2010 to 2011 and increased from 2011 to 2012.
B)increased from 2010 to 2011 and decreased from 2011 to 2012.
C)decreased from 2010 to 2011 and increased from 2011 to 2012.
D)decreased from 2010 to 2011 and decreased from 2011 to 2012.

Question

Table 15-1
Labor Data for Aridia
 $$\begin{array} { | l | c | c | c | } 
\hline \text { Year } & \mathbf { 2 0 1 0 } & \mathbf { 2 0 1 1 } & \mathbf { 2 0 1 2 } \
\hline \text { Adult population } & 2000 & 3000 & 3200 \
\hline \text { Number of emplayed } & 1400 & 1300 & 1600 \
\hline \text { Number of unemplayed } & 200 & 600 & 200 \
\hline
\end{array}$$
-Refer to Table 15-1. The unemployment rate of Aridia
A)increased from 2010 to 2011 and increased from 2011 to 2012.
B)increased from 2010 to 2011 and decreased from 2011 to 2012.
C)decreased from 2010 to 2011 and increased from 2011 to 2012.
D)decreased from 2010 to 2011 and decreased from 2011 to 2012.

Quizplus · Accepted Answer

To find the unemployment rate, we need to divide the number of unemployed by the adult population and multiply by 100. 
- In 2010, the unemployment rate was (200/2000) x 100 = 10%. 
- In 2011, the unemployment rate was (600/3000) x 100 = 20%, which is an increase from the previous year. 
- In 2012, the unemployment rate was (200/3200) x 100 = 6.25%, which is a decrease from the previous year. 
Therefore, the unemployment rate increased from 2010 to 2011 and decreased from 2011 to 2012. Option B is correct.

Table 15-1 Labor Data for Aridia -Refer to Table 15-1

Table 15-1
Labor Data for Aridia -Refer to Table 15-1