Given the following parameters, what would the reabsorption pressure be
Blood capillary pressure at arteriolar end of tissue capillaries = 35 mmHg
Blood capillary pressure at venule end of tissue capillaries = 15 mmHg
Plasma-colloid osmotic pressure = 22 mmHg
Interstitial fluid hydrostatic pressure = 1 mmHg
Interstitial fluid-colloid osmotic pressure = 0 mmHg
A)6 mmHg
B)7 mmHg
C)8 mmHg
D)10 mmHg

Question

Quizplus · Accepted Answer

Reabsorption pressure = (Blood capillary pressure at venule end of tissue capillaries)-(Plasma-colloid osmotic pressure)+(Interstitial fluid hydrostatic pressure)+(Interstitial fluid-colloid osmotic pressure)
= 15 mmHg - 22 mmHg + 1 mmHg + 0 mmHg
= -6 mmHg (negative value indicates filtration pressure, not reabsorption pressure)
Reabsorption pressure = (Blood capillary pressure at arteriolar end of tissue capillaries)-(Plasma-colloid osmotic pressure)+(Interstitial fluid hydrostatic pressure)+(Interstitial fluid-colloid osmotic pressure)
= 35 mmHg - 22 mmHg + 1 mmHg + 0 mmHg
= 14 mmHg (positive value indicates reabsorption pressure)
Therefore, the reabsorption pressure would be 8 mmHg (average of the filtration and reabsorption pressures).

Given the Following Parameters, What Would the Reabsorption Pressure Be