$\text { Data Table A }$
$\begin{array}{|l|l|l|l|l|}
\hline \begin{array}{c}
\text { Sample } \
\text { Number }
\end{array} & \text { Item 1 } & \text { Item 2 } & \text { /tem 3 } & \text { /tem 4 } \
\hline 1 & 13.10 & 13.90 & 12.80 & 13.20 \
\hline 2 & 13.80 & 13.00 & 12.50 & 12.70 \
\hline 3 & 14.00 & 12.90 & 13.10 & 13.50 \
\hline 4 & 12.30 & 13.30 & 12.80 & 13.60 \
\hline 5 & 13.10 & 12.60 & 13.30 & 12.90 \
\hline 6 & 12.50 & 13.40 & 12.80 & 13.30 \
\hline 7 & 13.60 & 12.70 & 13.30 & 13.80 \
\hline 8 & 12.50 & 13.50 & 13.10 & 12.90 \
\hline 9 & 13.00 & 13.60 & 12.70 & 13.20 \
\hline 10 & 12.80 & 12.90 & 12.70 & 13.30 \
\hline
\end{array}$
-Refer to Data .The mean of the ranges is ______.
A)1.00
B)0.7
C)1.7
D)0.27

Question

Quizplus · Accepted Answer

The range for each sample is the difference between the maximum and minimum values within that sample. Calculating the range for each sample and then finding the mean of these ranges gives:1. Sample 1: Range = 13.90 - 12.80 = 1.102. Sample 2: Range = 13.80 - 12.50 = 1.303. Sample 3: Range = 14.00 - 12.90 = 1.104. Sample 4: Range = 13.60 - 12.30 = 1.305. Sample 5: Range = 13.30 - 12.60 = 0.706. Sample 6: Range = 13.40 - 12.50 = 0.907. Sample 7: Range = 13.80 - 12.70 = 1.108. Sample 8: Range = 13.50 - 12.50 = 1.009. Sample 9: Range = 13.60 - 12.70 = 0.9010. Sample 10: Range = 13.30 - 12.70 = 0.60Mean of ranges = (1.10 + 1.30 + 1.10 + 1.30 + 0.70 + 0.90 + 1.10 + 1.00 + 0.90 + 0.60) / 10 = 1.00Therefore, the mean of the ranges is 1.00.

Data Table A \text { Data Table A } Data Table A -Refer to Data

$\text { Data Table A }$ -Refer to Data