An AP axial shoulder projection (Stryker method) with poor positioning that demonstrates the lesser tubercle in profile
1)also demonstrates an obscured greater tubercle.
2)was obtained because the humerus was elevated beyond vertical.
3)demonstrates the Hill-Sachs defect.
4)was obtained because the distal humerus was tilted laterally.
A) 1 and 2 only
B) 1 and 4 only
C) 2 and 3 only
D) 3 and 4 only

Question

Quizplus · Accepted Answer

A poorly positioned AP axial shoulder projection with the humerus elevated beyond vertical may result in the lesser tubercle being seen in profile, while the greater tubercle is obscured. Tilt of the distal humerus laterally may result in an AP projection with both the greater and lesser tubercles superimposed upon one another, making it difficult to discern lateral structures. Hill-Sachs defect is best demonstrated using an oblique view of the humerus.

An AP Axial Shoulder Projection (Stryker Method) with Poor Positioning