Solve each equation
-The population in a country is growing at the rate of 2.5% per year. If 7,638,000 people lived there in 1999, how many will there be in the year 2003? Use $y = y_0e^{0.025t}$ and round to the nearest ten thousand.

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The Answer of Solve each equation
-The population in a country is growing at the rate of 2.5% per year. If 7,638,000 people lived there in 1999, how many will there be in the year 2003? Use $y = y_0e^{0.025t}$ and round to the nearest ten thousand.

Solve Each Equation -The Population in a Country Is Growing y=y0e0.025ty = y_0e^{0.025t}y=y0​e0.025t

Solve Each Equation
-The Population in a Country Is Growing $y = y_0e^{0.025t}$