Assuming ptr is a pointer variable, what will the following statement output?
Cout

Question

Assuming ptr is a pointer variable, what will the following statement output?
Cout << *ptr;
A) the value stored in the variable whose address is contained in ptr
B) the string "*ptr"
C) the address of the variable whose address is stored in ptr
D) the address of the variable stored in ptr
E) None of these

Quizplus · Accepted Answer

The expression "*ptr" dereferences the pointer variable and returns the value stored at the memory address pointed to by ptr. The cout statement will output this value. Therefore, the correct answer is A.

Assuming Ptr Is a Pointer Variable, What Will the Following