Given the following code segment, what is the output?
int x = 1, y = 1, z = 1;
y = y + z;
x = x + y;
cout

Question

Given the following code segment, what is the output?
int x = 1, y = 1, z = 1;
y = y + z;
x = x + y;
cout << "result = " << (x < y ? y : x) << endl;
A) result = 0
B) result = 1
C) result = 2
D) result = 3
E) there will be no output

Quizplus · Accepted Answer

The code first increments `y` by `z` (1+1=2), then increments `x` by the new value of `y` (1+2=3). The ternary operator `(x < y ? y : x)` evaluates to `x` since `x` is not less than `y`, thus the output is "result = 3".

Given the Following Code Segment, What Is the Output