The acceleration of a block of mass $m$ being pulled by a constant force $F$ which is applied at an angle above the horizontal is given by $a=\frac{F \cos \theta-f m g+f F \sin \theta}{m}$ where $f$ is the coefficient of friction between the block and the surface and $g$ is the acceleration due to gravity. Find the angle that maximizes the block's acceleration when $f=0.52$.

Question

Quizplus · Accepted Answer

The Answer of The acceleration of a block of mass $m$ being pulled by a constant force $F$ which is applied at an angle above the horizontal is given by $a=\frac{F \cos \theta-f m g+f F \sin \theta}{m}$ where $f$ is the coefficient of friction between the block and the surface and $g$ is the acceleration due to gravity. Find the angle that maximizes the block's acceleration when $f=0.52$.

The Acceleration of a Block of Mass mmm Being Pulled by a Constant Force

The Acceleration of a Block of Mass $m$ Being Pulled by a Constant Force