The voltage applied to a $0.25-\mathrm{F}$ capacitor is given by $v=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}$. Find the current at $3.7 \mathrm{~s}$.

Name: The voltage applied to a $0.25-\mathrm{F}$ capacitor is given by $v=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}$. Find the current at $3.7 \mathrm{~s}$.
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The Answer of The voltage applied to a $0.25-\mathrm{F}$ capacitor is given by $v=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}$. Find the current at $3.7 \mathrm{~s}$.

The Voltage Applied to A 0.25−F0.25-\mathrm{F}0.25−F Capacitor Is Given By v=(t2−2t)35tv=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}v=5t(t2−2t)3​

The Voltage Applied to A $0.25-\mathrm{F}$ Capacitor Is Given By $v=\frac{\left(t^{2}-2 t\right)^{3}}{5 t}$