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Question 47
Multiply to show that (211−1−11012)\left(\begin{array}{ccc}2 & 1 & 1 \\ -1 & -1 & 1 \\ 0 & 1 & 2\end{array}\right)2−101−11112 and (0.60.2−0.4−0.4−0.80.60.20.40.2)\left(\begin{array}{ccc}0.6 & 0.2 & -0.4 \\ -0.4 & -0.8 & 0.6 \\ 0.2 & 0.4 & 0.2\end{array}\right)0.6−0.40.20.2−0.80.4−0.40.60.2 are inverses.
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Q42: Calculate
Q43: If Q44: If Q45: Three types of seating were availableQ46: Multiply to show that Q48: Calculate the inverse: Q49: Calculate the inverse: Q50: Calculate the inverse: Q51: Calculate the inverse: Q52: Calculate the inverse of
Q44: If Q45: Three types of seating were availableQ46: Multiply to show that Q48: Calculate the inverse: Q49: Calculate the inverse: Q50: Calculate the inverse: Q51: Calculate the inverse: Q52: Calculate the inverse of
Q45: Three types of seating were available
Q46: Multiply to show that
Q48: Calculate the inverse:
Q49: Calculate the inverse:
Q50: Calculate the inverse:
Q51: Calculate the inverse:
Q52: Calculate the inverse of
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