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Question 58
Solve. Leave your answers in fractional form: 3x+4y−z=13 x+4 y-z=13x+4y−z=1 2x−2y+z=0x+y−z=2\begin{array}{r}2 x-2 y+z=0 \\x+y-z=2\end{array}2x−2y+z=0x+y−z=2
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