A projectile is launched from the ground. Its height (metres) after $t$ seconds is given by $s=k t^{2}+v_{0} t$ where $k$ is a constant, $v_{0}$ is the initial velocity. If the height at $1.0 \mathrm{~s}$ is $8.7 \mathrm{~m}$ and the height at $1.5 \mathrm{~s}$ is $7.625 \mathrm{~m}$, determine the height at time $2.0 \mathrm{~s}$.

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The Answer of A projectile is launched from the ground. Its height (metres) after $t$ seconds is given by $s=k t^{2}+v_{0} t$ where $k$ is a constant, $v_{0}$ is the initial velocity. If the height at $1.0 \mathrm{~s}$ is $8.7 \mathrm{~m}$ and the height at $1.5 \mathrm{~s}$ is $7.625 \mathrm{~m}$, determine the height at time $2.0 \mathrm{~s}$.

A Projectile Is Launched from the Ground ttt Seconds Is Given By

A Projectile Is Launched from the Ground $t$ Seconds Is Given By