For a simply-supported $4.0 \mathrm{~m}$ beam carrying a uniform load of $3.5 \mathrm{~N} / \mathrm{m}$, the deflection at $x$ metres is given by $y=\frac{3.5}{24 k}\left(4.0^{3} x-8.0 x^{3}+x^{4}\right)$, where $k$ is a constant. If $k=41000000$, what is the deflection at $1.2 \mathrm{~m} ?$

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The Answer of For a simply-supported $4.0 \mathrm{~m}$ beam carrying a uniform load of $3.5 \mathrm{~N} / \mathrm{m}$, the deflection at $x$ metres is given by $y=\frac{3.5}{24 k}\left(4.0^{3} x-8.0 x^{3}+x^{4}\right)$, where $k$ is a constant. If $k=41000000$, what is the deflection at $1.2 \mathrm{~m} ?$

For a Simply-Supported 4.0 m4.0 \mathrm{~m}4.0 m Beam Carrying a Uniform Load Of 3.5 N/m3.5 \mathrm{~N} / \mathrm{m}3.5 N/m

For a Simply-Supported $4.0 \mathrm{~m}$ Beam Carrying a Uniform Load Of $3.5 \mathrm{~N} / \mathrm{m}$