The half-life of a chemical reaction, $t_{\frac{1}{2}}$, is the time it takes for half of the original substance to react. For certain reactions, the half-life is found by the equation $t_{\frac{1}{2}}=\frac{1}{k C_{0}}$ seconds, where $k$ is a constant (different for each reaction) and $C_{0}$ is the original concentration of reactant. Find $t_{\frac{1}{2}}$ if $k=0.487$ and $C_{0}=1.201$.

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The Answer of The half-life of a chemical reaction, $t_{\frac{1}{2}}$, is the time it takes for half of the original substance to react. For certain reactions, the half-life is found by the equation $t_{\frac{1}{2}}=\frac{1}{k C_{0}}$ seconds, where $k$ is a constant (different for each reaction) and $C_{0}$ is the original concentration of reactant. Find $t_{\frac{1}{2}}$ if $k=0.487$ and $C_{0}=1.201$.

The Half-Life of a Chemical Reaction t12t_{\frac{1}{2}}t21​​ , Is the Time It Takes for Half of the Time

The Half-Life of a Chemical Reaction $t_{\frac{1}{2}}$ , Is the Time It Takes for Half of the Time