A baseball player throws a ball with an initial velocity of 66 feet per second at an angle 43 degrees with the horizontal. What are the vertical and horizontal components of the velocity? Round to one decimal place.
A) vertical component = 45.0 ft/sec; horizontal component = 48.3 ft/sec
B) vertical component = 48.3 ft/sec; horizontal component = 45.0 ft/sec
C) vertical component = -54.9 ft/sec; horizontal component = 36.6 ft/sec
D) no solution

Question

Quizplus · Accepted Answer

The vertical component $V_v = V \sin(\theta)$ and the horizontal component $V_h = V \cos(\theta)$, where $V = 66$ ft/sec and $\theta = 43^\circ$. Thus, $V_v = 66 \sin(43^\circ) \approx 45.0$ ft/sec and $V_h = 66 \cos(43^\circ) \approx 48.3$ ft/sec.

A Baseball Player Throws a Ball with an Initial Velocity