Change $x^{2}+y^{2}-4 x-12 y=0$ into an equation in polar form.
A) $r=4 \cos \theta-12 \sin \theta$
B) $r=4 \cos \theta+12 \sin \theta$
C) $r^{2}=4 \cos \theta+12 \sin \theta$
D) $r=48 \cos \theta \sin \theta$

Question

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The Answer of Change $x^{2}+y^{2}-4 x-12 y=0$ into an equation in polar form.
A) $r=4 \cos \theta-12 \sin \theta$
B) $r=4 \cos \theta+12 \sin \theta$
C) $r^{2}=4 \cos \theta+12 \sin \theta$
D) $r=48 \cos \theta \sin \theta$

Change x2+y2−4x−12y=0x^{2}+y^{2}-4 x-12 y=0x2+y2−4x−12y=0 Into an Equation in Polar Form r=4cos⁡θ−12sin⁡θr=4 \cos \theta-12 \sin \thetar=4cosθ−12sinθ

Change $x^{2}+y^{2}-4 x-12 y=0$ Into an Equation in Polar Form $r=4 \cos \theta-12 \sin \theta$