Solve the equation.
-$\left|7-\frac{1}{3} x\right|=9$
A) $\{48,-6\}$
B) $\{-48,-6\}$
C) $\{-16,-2\}$
D) $\{-2,16\}$

Question

Quizplus · Accepted Answer

To solve the equation $\left|7-\frac{1}{3} x\right|=9$, we consider both cases where the expression inside the absolute value is positive and negative. 1. $7 - \frac{1}{3}x = 9$: Solving for $x$, we subtract 7 from both sides to get $-\frac{1}{3}x = 2$, then multiply both sides by -3 to find $x = -6$.2. $7 - \frac{1}{3}x = -9$: Solving for $x$, we add 9 to both sides to get $7 = -9 + \frac{1}{3}x$, which simplifies to $16 = \frac{1}{3}x$. Multiplying both sides by 3, we find $x = 48$.Therefore, the solution set is $\{48, -6\}$.

Solve the Equation ∣7−13x∣=9\left|7-\frac{1}{3} x\right|=9​7−31​x​=9 A) {48,−6}\{48,-6\}{48,−6} B) {−48,−6}\{-48,-6\}{−48,−6} C) {−16,−2}\{-16,-2\}{−16,−2} D) {−2,16}\{-2,16\}{−2,16}

Solve the Equation $\left|7-\frac{1}{3} x\right|=9$ A) $\{48,-6\}$ B) $\{-48,-6\}$ C) $\{-16,-2\}$ D) $\{-2,16\}$