Solve the problem.
-A mixture of chlorine and water contains a total of 45 gallons of liquid. There are 26 gallons of pure chlorine in the mixture. (i) What percent of the mixture is water? (ii) What percent of the mixture is chlorine? Round your answer to the nearest percent, if necessary.
A) (i) $42 \%$ water;(ii) $58 \%$ chlorine
B) (i) $64 \%$ water;(ii) $36 \%$ chlorine
C) (i) $58 \%$ water;(ii) $42 \%$ chlorine
D) (i) $26 \%$ water;(ii) $74 \%$ chlorine

Question

Quizplus · Accepted Answer

(i) To find the percent of water in the mixture, subtract the volume of chlorine (26 gallons) from the total volume (45 gallons) to get the volume of water, which is 19 gallons. Then, $ \frac{19}{45} \times 100 \approx 42\% $. (ii) The percent of chlorine is found by dividing the volume of chlorine by the total volume, $ \frac{26}{45} \times 100 \approx 58\% $.

Solve the Problem 42%42 \%42% Water;(ii) 58%58 \%58% Chlorine B) (I) 64%64 \%64%

Solve the Problem $42 \%$ Water;(ii) $58 \%$ Chlorine
B) (I) $64 \%$