Solve the equation.
-$42 \mathrm{~s}+20=12 \mathrm{~s}$

A) $\left\{\frac{10}{27}\right\}$

B) $\left\{-\frac{2}{3}\right\}$

C) $\left\{\frac{3}{2}\right\}$

D) $\left\{\frac{2}{3}\right\}$

Question

Solve the equation.
-$42 \mathrm{~s}+20=12 \mathrm{~s}$

A) $\left\{\frac{10}{27}\right\}$

B) $\left\{-\frac{2}{3}\right\}$

C) $\left\{\frac{3}{2}\right\}$

D) $\left\{\frac{2}{3}\right\}$

Quizplus · Accepted Answer

To solve the equation $42s + 20 = 12s$, first subtract $12s$ from both sides to get $30s + 20 = 0$. Then, subtract $20$ from both sides to get $30s = -20$. Finally, divide both sides by $30$ to solve for $s$, which gives $s = -\frac{20}{30} = -\frac{2}{3}$.

Solve the Equation 42 s+20=12 s42 \mathrm{~s}+20=12 \mathrm{~s}42 s+20=12 s A) {1027}\left\{\frac{10}{27}\right\}{2710​} B) {−23}\left\{-\frac{2}{3}\right\}{−32​} C) {32}\left\{\frac{3}{2}\right\}{23​} D) {23}\left\{\frac{2}{3}\right\}{32​}

Solve the Equation $42 \mathrm{~s}+20=12 \mathrm{~s}$ A) $\left\{\frac{10}{27}\right\}$ B) $\left\{-\frac{2}{3}\right\}$ C) $\left\{\frac{3}{2}\right\}$ D) $\left\{\frac{2}{3}\right\}$