Write the series with summation notation.
-$-2+3-4+5-6+7$

A) $\sum_{\mathrm{i}=1}^{6}(-1)^{\mathrm{i}} \cdot(\mathrm{i}+1)$

B) $\sum_{i=1}^{6}(-1)^{i+1} \cdot(i+1)$

C) $\sum_{i=1}^{6}(-1)^{\mathrm{i}+1} \cdot(\mathrm{i}+2)$

D) $\sum_{i=1}^{6}(-1)^{\mathrm{i}} \cdot(\mathrm{i}+2)$

Question

Write the series with summation notation.
-$-2+3-4+5-6+7$

A) $\sum_{\mathrm{i}=1}^{6}(-1)^{\mathrm{i}} \cdot(\mathrm{i}+1)$

B) $\sum_{i=1}^{6}(-1)^{i+1} \cdot(i+1)$

C) $\sum_{i=1}^{6}(-1)^{\mathrm{i}+1} \cdot(\mathrm{i}+2)$

D) $\sum_{i=1}^{6}(-1)^{\mathrm{i}} \cdot(\mathrm{i}+2)$

Quizplus · Accepted Answer

The series alternates between -2 and 3, starting with -2. The summation notation should reflect this pattern, with the alternating sign and the increasing term. Choice A correctly captures this pattern.

Write the Series with Summation Notation −2+3−4+5−6+7-2+3-4+5-6+7−2+3−4+5−6+7 A) ∑i=16(−1)i⋅(i+1)\sum_{\mathrm{i}=1}^{6}(-1)^{\mathrm{i}} \cdot(\mathrm{i}+1)∑i=16​(−1)i⋅(i+1) B) ∑i=16(−1)i+1⋅(i+1)\sum_{i=1}^{6}(-1)^{i+1} \cdot(i+1)∑i=16​(−1)i+1⋅(i+1)

Write the Series with Summation Notation $-2+3-4+5-6+7$ A) $\sum_{\mathrm{i}=1}^{6}(-1)^{\mathrm{i}} \cdot(\mathrm{i}+1)$ B) $\sum_{i=1}^{6}(-1)^{i+1} \cdot(i+1)$