Multiply or divide.
-$\frac{8 x+16}{x-1} \cdot \frac{3 x^{2}-6 x+3}{x^{2}-4}$

A) $\frac{24(x-1)}{x-2}$

B) $\frac{24(x-1)}{x+2}$

C) $\frac{8(x-1)}{x-2}$

D) $\frac{24(x+2)(x-1)}{x^{2}-4}$

Question

Multiply or divide.
-$\frac{8 x+16}{x-1} \cdot \frac{3 x^{2}-6 x+3}{x^{2}-4}$

A) $\frac{24(x-1)}{x-2}$

B) $\frac{24(x-1)}{x+2}$

C) $\frac{8(x-1)}{x-2}$

D) $\frac{24(x+2)(x-1)}{x^{2}-4}$

Quizplus · Accepted Answer

The correct answer is A because $\frac{8 x+16}{x-1} \cdot \frac{3 x^{2}-6 x+3}{x^{2}-4} = \frac{8(x+2)}{x-1} \cdot \frac{3(x-1)^{2}}{(x+2)(x-2)} = \frac{24(x-1)}{x-2}$.

Multiply or Divide 8x+16x−1⋅3x2−6x+3x2−4\frac{8 x+16}{x-1} \cdot \frac{3 x^{2}-6 x+3}{x^{2}-4}x−18x+16​⋅x2−43x2−6x+3​ A) 24(x−1)x−2\frac{24(x-1)}{x-2}x−224(x−1)​ B) 24(x−1)x+2\frac{24(x-1)}{x+2}x+224(x−1)​

Multiply or Divide $\frac{8 x+16}{x-1} \cdot \frac{3 x^{2}-6 x+3}{x^{2}-4}$ A) $\frac{24(x-1)}{x-2}$ B) $\frac{24(x-1)}{x+2}$